Solve the following pairs of equations

43x + 67y = –24, 67x + 43y = 24

Given pair of linear equations is


and …(ii)

On multiplying Eq. (i) by 43 and Eq. (ii) by 67 and then subtracting both of them, we get

Now, put the value of x in Eq. (i), we get

Hence, the required values of x and y are 1 and - 1, respectively.