If the first term of an AP is - 5 and the common difference is 2, then the sum of the first 6 terms is

Given,

First term, a = - 5

Common Difference, d = 2

Using the formula,

Where S_n is the sum of first n terms

n = no of terms

a = first term

d = common difference

S₄ = (6/2)[ 2 (- 5) + (6 - 1)2]

= 3 (- 10 + 10)

= 0