Match the AP’s given in column A with suitable common differences given in column B.



Column A




Column B



(A1)



2, - 2 – 6, - 10, …



(B1)





(A2)



a = - 18, n = 10, an = 0



(B2)



–5



(A3)



a = 0, a10 = 6



(B3)



4



(A4)



a2 = 13, a4 = 3



(B4)



–4





(B5)



2





(B6)







(B7)



5



(A1)


AP is 2, - 2, - 6, - 10, ….


So common difference is simply


a2 - a1 = - 2 - 2 = - 4 = (B3)


(A2)


Given


First term, a = - 18


No of terms, n = 10


Last term, an = 0


By using the nth term formula


an = a + (n - 1)d


0 = - 18 + (10 - 1)d


18 = 9d


d = 2 = (B5)


(A3)


Given


First term, a = 0


Tenth term, a10 = 6


By using the nth term formula


an = a + (n - 1)d


a10 = a + 9d


6 = 0 + 9d



= (B6)


(A4)


Let the first term be a and common difference be d


Given that


a2 = 13


a4 = 3


a2 - a4 = 10


a + d - (a + 3d) = 10


d - 3d = 10


- 2d = 10


d = - 5


= (B1)


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