Find the 12th term from the end of the AP – 2, - 4, - 6, …, - 100.


Given AP, – 2, - 4, - 6, …, - 100.


Here,


first term, a = - 2


common difference, d = - 4 – (2) = - 2


last term, l = - 100.


We know that, the nth term 'an' of an AP from the end is


an = l - (n - 1)d


where l is the last term and d is the common difference.


12th term from the end,


a12 = - 100 - (12 - 1) - 2


= - 100 + 22


= - 78


Hence, the 12th term from the end is - 78


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