ΔABC with vertices A(0 - 2, 0), B(2, 0) and C(0, 2) is similar to ΔDEF with vertices D( - 4, 0), E(4, 0) and F(0, 4).


True

Given,


ΔABC = ΔDEF


Now,


Calculate the distance between A (2, 0) and B (2, 0) in ΔABC;


Distance between the points (x1, y1) and (x2, y2);



So,



Similarly, distance between B (2, 0) and C (0, 2)



Distance between C (0, 2) and A (2, 0)



Now,


Calculate the distance between F (0, 4) and D ( - 4, 0) in ΔDEF;




Distance between F (0, 4) and E ( - 4, 0);



Distance between E (4, 0) and D ( - 4, 0);



Now,






Here, we see that sides of ΔABC and ΔFDE are proportional.



Hence, both the triangles are similar by SSS rule.


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