Find the area of the triangle whose vertices are ( - 8, 4), ( - 6, 6) and ( - 3, 9).
Given,
Let the vertices of triangle;
(x1, y1) → ( - 8, 4)
(x2, y2) = ( - 6, 6)
(x3, y3) = ( - 3, 9)
We know that, the area of triangle with vertices (x1, y1), (x2, y2) and (x3, y3)
Area of triangle = 1/2 [x1 (y2 - y3 ) + x2 (y3 - y1 ) + x3 (y1 - y2 )]=0
= 1/2 [ - 8(6 – 9) – 6(9 – 4) + ( - 3)(4 – 6)]
= 1/2 [ - 8( - 3) – 6(5) – 3( - 2)]
= 1/2 24 – 30 + 6)
= 1/2 (30 – 30)
= 1/2 (0) = 0
Hence, the area of triangle is 0.