The value of the expression
is
Given: 
⇒ 
⇒ 
(∵cos(90°-θ) = sin θ and sin(90°-θ) = cos θ)
⇒ 
⇒ 1/1 + 1 = 2
(Since, 
as by identity, sin2 θ +cos2 θ =1
So, 
and sin2 63° + cos2 63° = 1 )
∴ 
11
The value of the expression
is
Given:
⇒
⇒
(∵cos(90°-θ) = sin θ and sin(90°-θ) = cos θ)
⇒
⇒ 1/1 + 1 = 2
(Since, as by identity, sin2 θ +cos2 θ =1
So, and sin2 63° + cos2 63° = 1 )
∴