(3-cot300)=tan3600-2sin600


L.H.S: (√3 + 1) (3 – cot 30°)

= (√3 + 1) (3 – √3) [cos 30° = √3]


= (√3 + 1) √3 (√3 - 1) [(3 – √3) = √3 (√3 - 1)]


= ((√3)2– 1) √3 [ (√3+1)(√3-1) = ((√3)2 – 1)]


= (3-1) √3


= 2√3


Similarly solving R.H.S: tan3 60° - 2 sin 60°



[]


= 3√3 - √3


= 2√3


L.H.S = R.H.S


Hence, proved.


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