tan θ +tan (90 0 - θ ) = sec θ sec (90 0 - θ )

Question

Philoid · Accepted Answer

L.H.S: tan θ + tan (90° - θ)

= tan θ + cot θ

[∵tan (90° - θ) = cot θ]

= sec θ cosec θ

= sec θ sec (90° - θ) [∵cosec θ = sec (90° - θ)]

: R.H.S

Hence, proved.

tan θ +tan (900- θ) = sec θ sec (900- θ)