In the given figure, ABCD is a cyclic quadrilateral in which AB || DC and BAD = 100°. Then ABC = ?


Given: ABCD is a cyclic quadrilateral, AB||DC and BAD = 100°


Here,


BAD + BCD = 180° (opposite angles in cyclic quadrilateral are supplementary)


100° + BCD = 180°


BCD = 180° – 100°


BCD = 80°


Here, AB||DC and BC is the transversal


ABC + BCD = 180° (interior angles along the transversal are supplementary)


ABC + 80° = 180°


ABC = 180° – 80° = 100°


ABC = 100°

28
1