In the given figure, A and B are the centers of two circles having radii 5 cm and 3 cm respectively and intersecting at points P and Q respectively. If AB = 4 cm, then the length of common chord PQ is
Given: two circles having radii 6 cm and 3 cm
Construction: join AP
Consider ΔABP
Here,
AP2 = AB2 + BP2
52 = 42 + 32
25 = 16 + 9
25 = 25
∴ ΔABP is right angled triangle
PQ = 2×BP
PQ = 2×3 = 6cm
∴PQ = 6cm