In figure, if ∠AOB = 125°, then ∠COD is equal to

As in the given figure ABCD is a quadrilateral circumscribing the circle and we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle.

So, we have

∠AOB + ∠COD = 180°

125° + ∠COD = 180°

∠COD = 55°