In figure, AT is a tangent to the circle with center 0 such that OT = 4 cm and OTA = 30°. Then, AT is equal to


Given : A circle with center O and a tangent AT passing through point A on the circle, also OT = 4 cm and OTA = 30°


To find : Length of AT


Construction : Join OA.



We know that, the tangent at any point of a circle is perpendicular to the radius through the point of contact.


So we have


OA AT


Therefore, OAT = 90°


In OAT


Using



We have,




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