In gm ABCD, it is given that AB = 10cm, DL AB and BM AD such that DL = 6cm and BM = 8cm. Then, AD = ?


Given:


AB = 10cm


DL AB


BM AD


DL = 6cm


BM = 8cm


Now, consider the parallelogram ABCD


Here, let AB be the base of the parallelogram then DL becomes its altitude (height).


Area of the parallelogram is given by: Base × Height


area of gm ABCD = AB×DL = 10×6 = 60cm2


Now,


Consider AD as base of the parallelogram then BM becomes its altitude (height)


area of gm ABCD = AD × BM = 60cm2


AD × 8 = 60cm2


AD = 60/8 = 7.5cm


length of AD = 7.5cm.

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