In ‖gm ABCD, it is given that AB = 10cm, DL ⊥ AB and BM ⊥ AD such that DL = 6cm and BM = 8cm. Then, AD = ?
Given:
AB = 10cm
DL ⊥ AB
BM ⊥ AD
DL = 6cm
BM = 8cm
Now, consider the parallelogram ABCD
Here, let AB be the base of the parallelogram then DL becomes its altitude (height).
Area of the parallelogram is given by: Base × Height
∴ area of ‖gm ABCD = AB×DL = 10×6 = 60cm2
Now,
Consider AD as base of the parallelogram then BM becomes its altitude (height)
∴ area of ‖gm ABCD = AD × BM = 60cm2
AD × 8 = 60cm2
AD = 60/8 = 7.5cm
∴length of AD = 7.5cm.