In the adjoining figure, the point D divides the side BC of ∆ABC in the ratio m:n. Prove that ar(∆ABD): ar(∆ADC) = m:n.
Given: D divides the side BC of ∆ABC in the ratio m:n
Area (Δ ABD) = 1/2 × BD × AL
Area (Δ ADC) = 1/2 × CD × AL
Area (∆ABD): Area (∆ADC) = 1/2 × BD × AL: 1/2 × CD × AL
Area (∆ABD): Area (∆ADC) = BD: CD
Area (∆ABD): Area (∆ADC) = m: n (∵ BD:CD = m:n)