Check which of the following are solutions of the equation 2x – 3y = 6.
(i) (3, 0) (ii) (0, 2)
(iii) (2, 6) (iv) (6, 2)
(i) (3, 0)
2x – 3y = 6
LHS = 2x – 3y
Where x = 3 and y = 0,
Putting these values in 2x – 3y
⇒ 2×3 – 3×0
⇒ 6 – 0
⇒ 6 = RHS
Since, LHS = RHS therefore, (3, 0) satisfies 2x – 3y = 6
(ii) (0,2)
2x – 3y = 6
LHS = 2x – 3y
Where x = 0 and y = 2,
Putting these values in 2x – 3y
⇒ 2×0 – 3×2
⇒ 0 – 6
⇒ – 6 ≠ RHS
Since, LHS ≠RHS therefore, (0, 2) does not satisfy 2x – 3y = 6
(iii) (2, 6)
2x – 3y = 6
LHS = 2x – 3y
Where x = 2 and y = 6,
Putting these values in 2x – 3y
⇒ 2×2 – 3×6
⇒ 4 – 18
⇒ – 14≠ RHS
Since, LHS ≠RHS therefore, (2, 6) does not satisfy 2x – 3y = 6
(iv) (6, 2)
2x – 3y = 6
LHS = 2x – 3y
Where x = 6 and y = 2,
Putting these values in 2x – 3y
⇒ 2×6 – 3×2
⇒ 12 – 6
⇒ 6 = RHS
Since, LHS = RHS therefore, (6, 2) satisfies 2x – 3y = 6