Check which of the following are solutions of the equation 2x – 3y = 6.

(i) (3, 0) (ii) (0, 2)


(iii) (2, 6) (iv) (6, 2)


(i) (3, 0)


2x – 3y = 6


LHS = 2x – 3y


Where x = 3 and y = 0,


Putting these values in 2x – 3y


2×3 – 3×0


6 – 0


6 = RHS


Since, LHS = RHS therefore, (3, 0) satisfies 2x – 3y = 6


(ii) (0,2)


2x – 3y = 6


LHS = 2x – 3y


Where x = 0 and y = 2,


Putting these values in 2x – 3y


2×0 – 3×2


0 – 6


– 6 RHS


Since, LHS ≠RHS therefore, (0, 2) does not satisfy 2x – 3y = 6


(iii) (2, 6)


2x – 3y = 6


LHS = 2x – 3y


Where x = 2 and y = 6,


Putting these values in 2x – 3y


2×2 – 3×6


4 – 18


– 14 RHS


Since, LHS ≠RHS therefore, (2, 6) does not satisfy 2x – 3y = 6


(iv) (6, 2)


2x – 3y = 6


LHS = 2x – 3y


Where x = 6 and y = 2,


Putting these values in 2x – 3y


2×6 – 3×2


12 – 6


6 = RHS


Since, LHS = RHS therefore, (6, 2) satisfies 2x – 3y = 6


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