Study the graph given below. Choose the equation whose graph is given:
(i) y = x (ii) y = 2x
(iii) y = 2x + 1 (iv) x + y = 0
To find the correct answer, we will try all the options.
There are two points given,
A = (1, 3) and B = ( – 1, – 1)
We will put them in all the equations and check whether they satisfy or not.
(i) y = x
When x = 1 then, y = x
⇒ y = 1 ≠ 3
So it does not satisfy y = x
Therefore, the graph does not satisfy y = x
(ii) y = 2x
When x = 1 then, y = 2x
⇒ y = 2 × 1
⇒ y = 2 ≠ 3
So it does not satisfy y = 2x
Therefore, the graph does not satisfy y = 2x
(iii) y = 2x + 1
When x = 1 then, y = 2x + 1
⇒ y = 2 × 1 + 1
⇒ y = 2 + 1
⇒ y = 3
So it satisfies y = 2x
Now When x = – 1 then, y = 2x + 1
⇒ y = 2 × – 1 + 1
⇒ y = – 2 + 1
⇒ y = – 1
So it also satisfies y = 2x
Therefore, the graph satisfies y = 2x + 1
(iv) x + y = 0
When x = 1 then, y = – x
⇒ y = – 1 ≠ 3
So it does not satisfy x + y = 0
Therefore, the graph does not satisfy x + y = 0