Find the points where the graph of the equation 3x + 4y = 12 cuts the x-axis and the y-axis.
Given equation, 3x + 4y = 12
⇒ 4y = 12 – 3x
When x = – 4, then,
⇒ y = 6
When x = 0, then,
⇒ y = 3
When x = 4, then,
⇒ y = 0
Thus we have the following table,
X | – 4 | 0 | 4 |
Y | 6 | 3 | 0 |
On plotting the points, ( – 4, 6), (0, 3) and (4, 0) we get the following graph,
Clearly from the graph, it cuts x axis at (4, 0) and y axis at (0, 3)
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