A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to Is this correct? Give reasons.


No, this is not correct.

Suppose we throw a die, then total number of outcomes = 6


Possible outcomes = 1or 2or 3or 4or 5or 6


Probability of getting 1 = 1/6


Now, probability of getting not 1 = 1 – Probability of getting 1


= 1 - 1/6 = 5/6


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