A bag contains 10 red, 5 blue and 7 green balls. A ball is drawn at random. Find the probability of this ball being a

(i) red ball


(ii) green ball


(iii) not a blue ball


No. of red ball = 10

No. of blue ball = 5


No. of green balls = 7


If a ball is drawn out of 22 balls (5 blue
+ 7 green + 10 red), then the total number of outcomes are


n(S) = 22


(i) Let E1 = Event of getting a red ball


n(E1) = 10



(ii) Let E2 = Event of getting a green ball


n(E2) = 7



(iii) Let E3 = Event getting a red ball or a green ball i.e., not a blue ball.


n(E3) = (10 + 7) = 17



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