If in ∆ABC and ∆DEF, then they will be similar, when


Given,

∆ABC and ∆EDF,


AB/DE = BC/FD



By converse of basic proportionality theorem, that if a line divides any two sides of a triangle in the same ratio, then the line must be parallel to the third side.


As we have,


∆ABC ∆EDF


Then,


B = D,


A = E and,


C = F

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