In figure, if ∠ D = ∠ C, then it is true that ∆ADE ∼ ∆ACB? Why?

Question

Philoid · Accepted Answer

(True)

In ∆ADE and ∆ACB,

Given,

∠D = ∠C

∠A = ∠A [common angle]

As we know sum of all the angles of a triangle is equals to 180∘.

So, by angle sum property of triangle the third angle of both triangles must be equal.

∠E = ∠B

∴ ∆ADE ∼ ∆ACB [by AAA similarity criterion]

In figure, if ∠D = ∠C, then it is true that ∆ADE ∼ ∆ACB? Why?