If ∆ABC ∆DEF, AB = 4 cm, DE = 6, EF = 9 cm and FD = 12 cm, then find the perimeter of ∆ABC.


Given,

AB = 4 cm,


DE = 6 cm


EF = 9 cm and


FD = 12 cm


Also,


∆ABC ∆DEF


We have,



By taking first two terms, we have



And by taking last two terms, we have,



Now,


Perimeter of ∆ABC = AB + BC + AC


= 4 + 6 + 8 = 18 cm


Thus, the perimeter of the triangle is 18 cm.


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