A 15 high tower casts a shadow 24 long at a certain time and at the same time, a telephone pole casts a shadow 16 long. Find the height of the telephone pole.


Given,

Let,



QR = 15 m (height of tower)


PQ = 24 m (shadow of tower)


At that time RPQ = θ


Again, let YZ = h be a telephone pole and its shadow XY = 16 m.


The same time YXZ = θ


Here, ABC and ∆DEF both are right angles triangles.


In ∆PQR and ∆XYZ,


RPQ = YXZ = θ


Q = Y [each 90°]


∆PQR XYZ [by AAA similarity criterion]


Then,



Hence, the height of the telephone pole is 10 m.


14
1