In the given figure, AB || CD. If ∠ CAB = 80° and ∠ EFC = 25°, then ∠ CEF = ?

Question

Philoid · Accepted Answer

AB || CD

BAC = DCF = 80^o

ECF + DCF = 180^o (linear pair of angles)

ECF =100^o

Now in triangle CFE,

ECF + EFC + CEF = 180^o

CEF = 180^o – 100^o – 25^o

=55^o

In the given figure, AB || CD. If ∠CAB = 80° and ∠EFC = 25°, then ∠CEF = ?