In the given figure, AB || CD. If ∠APQ = 70° and ∠PRD = 120°, then ∠QPR = ?
APQ =PQR =70o
Now, in triangle PQR, we have
PQR + PRQ + QPQ =180o
70 + 60 + QPQ =180o
QPQ =180o – 130o
=50o