Side BC of ΔABC has been produced to D on left hand side and to E on right hand side such that ∠ABD = 125° and ∠ACE = 130°. Then ∠A = ?
ABD +
ABC = 180 (Linear pair of angles)
ABC = 180o – 125o=55o
ACE +
ACB = 180 (Linear pair of angles)
ACB = 180o – 130o=50o
As we know that
ACB +
ABC +
BAC = 180o
BAC = 180 – 55 – 50
=75o