In the given figure, BO and CO are the bisectors of B and C respectively. If A = 50°, then BOC = ?


In ∆ABC,


A + B + C=180°


50° + B + C=180°


B + C=180°−50°=130°


B = 65°


C = 65°


Now in ∆OBC,


OBC + OCB + BOC=180°


BOC = 180° – 65° (OBC + OCB = 65 because O is bisector of B and C)


= 115°

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