In the given figure, BAD || EF, ∠AEF = 55° and ∠ACB = 25°, find ∠ABC.
According to question EF || BAD
Producing E to O, we get
EFA +
AEO = 180 (Linear pair of angles)
AEO = 180 – 55
= 125
Now, in triangle ABC we get,
A = 125 and
C = 25
So, ABC = 180 – (
A +
C)
= 180 – (125 + 25)
= 180 – 150
= 30O