In the given figure, BE ⊥ AC, ∠ DAC = 30° and ∠ DBE = 40°. Find ∠ ACB and ∠ ADB.

Question

Philoid · Accepted Answer

In triangle BEC we have,

B = 40^O and E = 90^O

So,C = 180^O – (90 + 40)

=50^O

Therefore,ACB = 50^O

Now intriangle ADC we have,

A = 30^O and C = 50^O

So,D = 180^O – (30 + 50)

=100^O

Therefore,

ADB + ADC = 180 (sum of angles on straight line)

ADB + 100 = 180

ADB = 180 – 100

= 80^O

In the given figure, BE ⊥ AC, ∠DAC = 30° and ∠DBE = 40°. Find ∠ACB and ∠ADB.