If ∠A, ∠B, ∠C and ∠D of a quadrilateral ABCD taken in order, are in the ratio 3 : 7 : 6: 4, then ABCD is a
Let the required angles be 3x, 7x, 6x and 4x
3x + 7x + 6x + 4x = 360° (Sum of angles of quadrilateral)
20x = 360°
x = 18°
Hence, angles are:
3x = 3 ⨯18° = 54°
7x = 7 ⨯ 18° = 126°
6x = 6 ⨯ 18° = 108°
4x = 4 ⨯18° = 72°
Now we can observe that, 54° + 126° = 180° and 72° + 108° = 180°
Thus, ABCD is a trapezium.
Hence option C is correct.