In the given figure, AC is a diagonal of quad. ABCD in which BL AC and DM AC. Prove that or (quad. ABCD)


Here we have ABCD as a quadrilateral with one of its diagonal as AC and BL and DM are perpendicular to AC

Thus, ar(ABCD) = ar(∆ADC) + ar(∆ABC)


Since, (BL AC) and (DM AC)


Area of ABCD = ( AC BL) + ( AC DM)


= AC (BL + DM)


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