To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is

Question

To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is

Philoid · Accepted Answer

To construct a triangle similar to a triangle, with its sides x/y of the corresponding sides of given triangle, the minimum number of points to be located at an equal distance is equal to the greater of m and n in m/n.

Here, m:n = 8:5 or m/n = 8/5

So, the minimum number of point to be located at equal distance on ray BX is 8.

Here, m:n = 8:5 or m/n = 8/5

So, the minimum number of point to be located at equal distance on ray BX is 8.