Draw a ∆ABC in which AB=5 cm, BC=6 cm, and ABC=60°. Construct a triangle similar to ABC with scale factor Justify the construction.


Steps of construction

1. Draw a line AB=5 cm.


2. Draw ABY=60° on which take a length BC=6 cm.


3. Join AC.


4. Draw any ray AX downwards making an acute angle.


5. Mark 7 points B1,B2,B3,B4,B5,B6 and B7 on AX1 such that AB1=B1B2=B2B3=


B3B4=B4B5=B5B6=B6B7


6. Join B7B and from B5 draw B5M||B7B intersecting AB at M.


7. Draw MN││BC intersecting AC at N Then, ∆AMN is the required triangle whose sides are equal to of the corresponding sides of ∆ABC.



By construction,


B5M││B7B


AM/MB = 5/2


Now,




Also,


MN||BC


Δ AMN ~ ΔABC



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