The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is


Clearly, the given bucket is in the form of frustum of a cone.


And we know



Curved surface area of frustum of a cone = πl(r1 + r2)


Where, l = slant height,


r1 and r2 are radii (r1 > r2)


For given bucket,


Radius of top, r1 = 28 cm


Radius of bottom, r2 = 7 cm


Slant height, l = 45 cm


Therefore,


Curved surface area of bucket = π(45)(28 + 7)



= 4950 cm2


So, the curved surface area of bucket is 4950 cm2.

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