Construct a ΔABC in which ∠B = 60°, ∠C = 45° and the length of perpendicular from vertex A to base BC as 5 cm.
Steps of Construction
1. Draw a line segment XY.
2. Take any point P on XY and draw PQ⊥XY.
3. Along PQ, set off PA= 5 cm
4. Through A, draw LM∥XY.
5. Construct ∠LAB=60° and ∠MAC=45° meeting XY at B and C respectively.
Therefore, ΔABC is the required triangle.