Construct a ΔABC in which base BC = 5.2 cm, ∠B = 60° and (AB + AC) = 7.6 cm.
Steps of Construction
1. Draw BC = 5.2 cm
2. Construct ∠CBX=60°
3. Along BX set off BP = 7.6 cm
4. Join CP.
5. Draw the perpendicular bisector of CP to intersecting BP at A.
6. Join AC.
Therefore, ΔABC is the required triangle.