The zeros of the polynomial x^{2} – 2x – 3 are

We have, f(x) = x^{2} – 2x – 3

Now, put f(x) = 0

x^{2} – 2x – 3 = 0

x^{2} – 3x + x – 3 = 0

x(x – 3) + 1(x – 3) = 0

(x – 3)(x + 1) = 0

Thus, x = 3, -1

Hence, option C is correct.