The zeros of the polynomial x^{2} ‒ √2 x – 12 are

We have, f(x) = x^{2} ‒ x – 12

Now, put f(x) = 0

x^{2} ‒ x – 12 = 0

x(x ‒ 3√2) + 2√2 x – 3√2)=0

(x ‒ 3√2) + (x + 2√2) = 0

Thus, x= 3√2 , -2√2

Hence option B is correct.