The zeros of the polynomial 
are
We have, f(x) = x2 + 
x – 2
f(x) = 6x2 + x – 12 =0
Now, put f(x) = 0
6x2 + x – 12 = 0
6x2 + 9x – 8x – 12 = 0
3x(2x + 3) -4(2x + 3) = 0
Hence, option B is correct.
6
The zeros of the polynomial are
We have, f(x) = x2 + x – 2
f(x) = 6x2 + x – 12 =0
Now, put f(x) = 0
6x2 + x – 12 = 0
6x2 + 9x – 8x – 12 = 0
3x(2x + 3) -4(2x + 3) = 0
Hence, option B is correct.