The zeros of the polynomial are

We have, f(x) = x^{2} + x – 2

f(x) = 6x^{2} + x – 12 =0

Now, put f(x) = 0

6x^{2} + x – 12 = 0

6x^{2} + 9x – 8x – 12 = 0

3x(2x + 3) -4(2x + 3) = 0

Hence, option B is correct.