How many terms are there in the AP 6, 10, 14, 18, ... , 174?
In the given AP, the first term = a = 6
Common difference = d = 10 - 6 = 4
Last term = 174
To find: No. of terms in the AP.
Since, we know that
an = a + (n - 1) × d
∴ 174 = 6 + (n - 1) × 4
⇒ 174 - 6 = 4n - 4
⇒ 168 = 4n - 4
⇒ 168 + 4= 4n
⇒ 4n = 172
⇒ n = 172/4
⇒ n = 43
∴ Number of terms = 43.