How many terms are there in the AP 6, 10, 14, 18, ... , 174?


In the given AP, the first term = a = 6

Common difference = d = 10 - 6 = 4


Last term = 174


To find: No. of terms in the AP.


Since, we know that


an = a + (n - 1) × d


174 = 6 + (n - 1) × 4


174 - 6 = 4n - 4


168 = 4n - 4


168 + 4= 4n


4n = 172


n = 172/4


n = 43


Number of terms = 43.


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