Which term of the AP 72, 68, 64, 60, ... is 0?


In the given AP, the first term = a = 72

Common difference = d = 68 - 72 = - 4


To find: place of the term 0.


So, let an = 0


Since, we know that


an = a + (n - 1) × d


0 = 72 + (n - 1) × (-4)


0 - 72 = - 4n + 4


- 72 - 4 = - 4n


- 76 = - 4n


n = 76/4


n = 19


19th term of the AP is 0.


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