Which term of the AP 72, 68, 64, 60, ... is 0?
In the given AP, the first term = a = 72
Common difference = d = 68 - 72 = - 4
To find: place of the term 0.
So, let an = 0
Since, we know that
an = a + (n - 1) × d
∴ 0 = 72 + (n - 1) × (-4)
⇒ 0 - 72 = - 4n + 4
⇒ - 72 - 4 = - 4n
⇒ - 76 = - 4n
⇒ n = 76/4
⇒ n = 19
∴ 19th term of the AP is 0.