The 9th term of an AP is - 32 and the sum of its 11th and 13th terms is - 94. Find the common difference of the AP.
Let a be the first term and d be the common difference.
Given: a9 = - 32
a11 + a13 = - 94
To find: common difference = d
Now, Consider a9 = - 32
⇒ a + (9 - 1)d = - 32
⇒ a + 8d = - 32 ……….(1)
Consider a11 + a13 = - 94
⇒ a + (11 - 1)d + a + (13 - 1)d = - 94
⇒ 2a + 22d = - 94
⇒ a + 11d = - 57 ……..(2)
Subtracting equation (1) from equation (2), we get,
3d = - 15
⇒ d = - 5
∴ Common difference = d = - 5