The first and last terms of an AP are a and 1 respectively. Show that the sum of the nth term from the beginning and the nth term from the end is (a + 1).
Let d be the common difference of the AP.
First term = a
Last term = l = 1
nth term from beginning of an AP is given by:
an = a + (n - 1)d …………………………….(1)
nth term from the end of an AP is given by:
Tn = l - (n - 1)d
= 1 - (n - 1)d …………………………….(2)
Sum of the nth term from the beginning and end is given by:
an + Tn = a + (n - 1)d + 1 - (n - 1)d
= a + 1
Hence, proved.