The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y.

Question

Philoid · Accepted Answer

Since, the terms are in an AP, therefore

(3y + 5) - (3y - 1) = (5y + 1) - (3y + 5)

⇒ 6 = 2y - 4

⇒ 2y = 10

⇒ y = 5

∴ y = 5