If (2p + 1), 13, (5p – 3) are in AP, find the value of p.
Since, the terms are in an AP, therefore
13 - (2p + 1) = (5p - 3) - (13)
⇒ 12 - 2p = 5p - 16
⇒ 7p = 28
⇒ p = 4
∴ p = 4