The sum of the first n terms of an AP is . Find its nth term and the 25th term.
Let an be the nth term of the AP.
To find: an and a25
Since, an =Sn - Sn - 1
= ( ) - (
)
= 1/2 (3n2 + 5n) - 1/2 [3(n - 1)2 + 5(n - 1)]
= 1/2 (3n2 + 5n - 3n2 - 3 + 6n - 5n + 5)
= 1/2 (6n - 2)
= 3n + 1
Since an = 5n - 1
∴ For 25th term, put n = 25, we get,
a25 = 3(25) + 1
= 75 + 1
= 76