If 4, x 1 , x 2 , x 3 , 28 are in AP then x 3 = ?

Question

Philoid · Accepted Answer

Here, first term = a = 4

Last term = l = 28

Number of terms = n = 5

∴ l = a + (n - 1)d

⇒ 28 = 4 + (5 - 1)d

⇒ 28 - 4 = 4d

⇒ 4d = 24

⇒ d = 6

Therefore x₃ = a + 3d

= 4 + 3(6)

= 4 + 18

= 22

If 4, x1, x2, x3, 28 are in AP then x3 = ?