If the nth term of an AP is (2n + 1), then the sum of its first three terms is
Given: nth term = 2n + 1
∴ an = 2n + 1
Put n= 1, a1 = 3
Put n= 2, a2 = 5
Put n= 3, a3 = 7
Now, sum of first three terms = 3 + 5 + 7 = 15