If the nth term of an AP is (2n + 1), then the sum of its first three terms is


Given: nth term = 2n + 1


an = 2n + 1


Put n= 1, a1 = 3


Put n= 2, a2 = 5


Put n= 3, a3 = 7


Now, sum of first three terms = 3 + 5 + 7 = 15

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