If an denotes the nth term of the AP 3, 8, 13, 18, ... then what is the value of (a30 - a20)?


Here, First term = a = 3


Common difference = d = 8 - 2 = 5


To find: a30 – a20


So, nth term is given by:


an = a + (n - 1)d


30th term is:


a30 = 3 + (30 - 1) × 5


= 3 + 145


= 148


Now, 20th term is:


a20 = 3 + (20 - 1) × 5


= 3 + 95


= 98


Now, (a30 – a20) = 148 - 98


= 50


(a30 – a20) = 50

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